Notes on Complex Analysis
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§2.1 The Extended Complex Plane and its Spherical Representation

2.1 The Extended Complex Plane and its Spherical Representation

All complex numbers form a field that extends the real number field. A complex number 𝛼+i𝛽 can be visualized on a rectangular plane as the point (𝛼,𝛽), with two axes: the real axis and the imaginary axis. It is well known that any complex number also has the polar form 𝑟ei𝜃=𝑟(cos𝜃+isin𝜃).

The point at infinity, ∞, extends ℂ to

ℂ̂=ℂ∪{∞}.

The following arithmetic operations are defined: for all 𝑎∈ℂ,

𝑎+∞=∞+𝑎=∞,

and for all 𝑏∈ℂ∖{0},

𝑏·∞=∞·𝑏=∞,𝑎∞=0.

Let

𝑆2={(𝑥1,𝑥2,𝑥3)∈ℝ3:𝑥12+𝑥22+𝑥32=1}.

There exists a stereographic projection of 𝑆2 onto ℂ̂. For every point other than (0,0,1), there is a corresponding complex number

𝑧=𝑥1+i𝑥21−𝑥3.(2.1.1)

This correspondence between ℂ and 𝑆2∖{(0,0,1)} is injective. In fact, the inverse can be solved for:

|𝑧|2=1−𝑥32(1−𝑥3)2=1+𝑥31−𝑥3,

which results in

𝑥3=|𝑧|2−1|𝑧|2+1,

and consequently,

𝑥1=ℜ𝔢(𝑧)(1−𝑥3)=𝑧+𝑧‾|𝑧|2+1,
𝑥2=ℑ𝔪(𝑧)(1−𝑥3)=𝑧−𝑧‾i|𝑧|2+i.

By letting ∞ correspond to (0,0,1), the bijection is complete. The sphere 𝑆2 is also called the Riemann sphere. The region given by the disk |𝑧|<1 corresponds to 𝑥3<0, and the region |𝑧|>1 corresponds to 𝑥3>0.

We will now give a geometric visualization of this projection. Let 𝑧=𝑥+i𝑦. Then we obtain

𝑥=𝑥11−𝑥3and𝑦=𝑥21−𝑥3.

Therefore,

𝑥:𝑦:1=𝑥1:𝑥2:1−𝑥3.

It follows that the points (0,0,0), (𝑥,𝑦,1), and (𝑥1,𝑥2,1−𝑥3) are collinear in ℝ3. Under the linear map

𝐯↦𝐯(10001000−1)+(0,0,1),

we get that (0,0,1), (𝑥,𝑦,0), and (𝑥1,𝑥2,𝑥3) are collinear. In other words, this correspondence is a central projection with center (0,0,1), projecting the points from 𝑆2∖(0,0,1) onto ℂ. Let this center correspond to ∞. In this representation, ∞∈ℂ̂ is no longer considered to be “special”.

It is worth noting that in several geometric contexts, an alternative paradigm exists where we let 𝑆 be the sphere centered at (0,0,12) of diameter 1, and project points from the north pole (0,0,1) onto the horizontal plane of tangency. The corresponding equations are then

𝑥1=ℜ𝔢(𝑧)|𝑧|2+1,𝑥2=ℑ𝔪(𝑧)|𝑧|2+1,𝑥3=|𝑧|2|𝑧|2+1.

The forward projection remains unchanged. Lastly, we define the upper half-plane; for the following sections, let

ℍ+={𝑧∈ℂ:ℑ𝔪(𝑧)>0}