§11.4 Hartogs’ Phenomenon
11.4 Hartogs’ Phenomenon
One of the most prominent results of complex function theory is Hartogs’ phenomenon, which reveals a fundamental difference between holomorphic functions of one variable and those of several variables. First discovered by Friedrich Hartogs in 1906, it essentially states that holomorphic functions in several complex variables exhibit a surprising rigidity.
To understand the sense of Hartogs’ phenomenon, consider the simple example of in one complex variable. This function is holomorphic on with a singularity at that cannot be removed. However, in the case of several complex variables, Hartogs’ phenomenon asserts that if a function is holomorphic in a domain that excludes a compact subset, it can be extended to a holomorphic function on the entire domain, including the excluded subset. One immediate conclusion from this is that isolated singularities are always removable in higher dimensions.
Theorem 11.4.1 (Hartogs’ Extension Theorem).
Let () be a domain and be a compact subset such that is connected. Then any holomorphic function has a unique extension to a holomorphic function such that on .Hartogs, in 1906, first proved his extension theorem using an integral formula, but was considered to be incomplete with gaps. In 1939, Fueter gave a proof for the case , and later Bochner and Martinelli developed more general integral kernel methods for higher dimensions. Finally, Ehrenpreis, in 1961, provided a succinct and analytic proof using the operator: by multiplying the function by a smooth cutoff or bump function and then solving a -problem to correct the non-holomorphy introduced by the cutoff, one can construct the desired extension.
The general study of complex function theory in multiple variables is made practical with the definition of differential forms in multiple variables and in particular the -problem, whose utility in a single variable has already been preluded to many times before.
Only certain cases of Theorem 11.4.1 are proved here.
Proposition 11.4.2.
Let be a Reinhardt domain centered at . Let be holomorphic. Then admits the unique Laurent expansion
converging absolutely and uniformly on compact subsets of .Proof.
Let with each . Since is a Reinhardt domain, for every the point
lies in ; moreover, the set of all such points, , is compact in . Assuming that a Laurent expansion exists and converges uniformly on this compact set, termwise integration on both sides of gives
which shows that the coefficients are uniquely determined.
To prove the existence of such an expansion, again fix . Because is Reinhardt, there exists such that the polyannulus
is contained in . On this set one may perform one-variable Laurent expansions (Theorem 4.1.3) successively in each coordinate, holding the others fixed. Since is holomorphic on , this procedure yields
a Laurent series converging uniformly on a neighborhood of . If , then the same construction gives
By uniqueness of Laurent coefficients (in the one-variable expansions), it follows that . Thus the coefficient functions are locally constant on , and since is connected they are constant throughout ; we therefore write them simply as .
Consequently,
holds in a neighborhood of every point in . If is compact, then is an open cover of , and hence it admits a finite subcover. Then the uniform convergence of the series on follows from the uniform convergence on each in the subcover. The absolute convergence follows from the absolute convergence of the one-variable Laurent expansions used in the construction.
Proposition 11.4.3.
Let be a Reinhardt domain centered at such that satisfies the condition that for every , there exists a point in of the form ( is the -th unit vector and ). Then any holomorphic function has the expansion
which converges locally uniformly and absolutely on .Proof.
By Proposition 11.4.2, has an expansion matching the form of (11.4.1). Now for a fixed , if not all ’s with are zero, then fixing all variables except gives a Laurent expansion that does not uniformly converge on all compact neighborhoods of (either a pole or an essential singularity with respect to ). Thus, we are left only with containing nonnegative components, and the conclusion holds. Theorem 11.4.4 (Hartogs’ Extension Theorem for Reinhardt Domains).
Let be a Reinhardt domain centered at such that satisfies the condition that for every , there exists a point in of the form ( is the -th unit vector and ). Let be holomorphic. Then can be analytically continued to the complete Reinhardt domain defined by
In other words, holomorphic such that on .Proof.
By Proposition 11.4.3, has the expansion
which absolutely converges on . Substituting for with for each gives
which converges. The function is then holomorphic as it is given by a power series expansion, and it satisfies on . Example 11.4.5.
Set and let
define a Reinhardt domain. Then any holomorphic function can be analytically continued to the entire unit ball by Theorem 11.4.4.